0=16t^2-96t+7

Solution for 0=16t^2-96t+7 equation:

0=16t^2-96t+7

We move all terms to the left:

0-(16t^2-96t+7)=0

We add all the numbers together, and all the variables

-(16t^2-96t+7)=0

We get rid of parentheses

-16t^2+96t-7=0

a = -16; b = 96; c = -7;
Δ = b2-4ac
Δ = 962-4·(-16)·(-7)
Δ = 8768
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{8768}=\sqrt{64*137}=\sqrt{64}*\sqrt{137}=8\sqrt{137}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(96)-8\sqrt{137}}{2*-16}=\frac{-96-8\sqrt{137}}{-32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(96)+8\sqrt{137}}{2*-16}=\frac{-96+8\sqrt{137}}{-32}
$